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Solve Quadratic Equations Step by Step

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Photo Math Solver Solved
x25x+6=0x^2 - 5x + 6 = 0
  1. 1Look for two numbers that multiply to 66 and add to 5-5: they are 2-2 and 3-3.
  2. 2Factor: (x2)(x3)=0(x - 2)(x - 3) = 0.
  3. 3Set each factor to zero: x2=0x - 2 = 0 or x3=0x - 3 = 0.
  4. 4Solve: x=2x = 2 or x=3x = 3.
01Definition

What is a quadratic equation?

A quadratic equation is a polynomial equation of degree two — the highest power of the variable is a square. In standard form it is written ax2+bx+c=0ax^2 + bx + c = 0, where aa, bb, and cc are numbers and a0a \neq 0. If aa were zero, the x2x^2 term would vanish and the equation would just be linear.

Graphically, the left side y=ax2+bx+cy = ax^2 + bx + c draws a parabola, and solving the equation means finding where that parabola crosses the x-axis. That is why a quadratic equation has at most two real solutions (called roots or zeros): a parabola can cross the axis twice, touch it once, or miss it entirely.

Which of those three cases you are in is decided by the discriminant, b24acb^2 - 4ac. Positive means two real roots, zero means one repeated root, and negative means the parabola never reaches the axis — the two roots are complex numbers instead.

Where you'll actually use this

  • Projectile motion: the height of a thrown ball over time is a quadratic, and its roots tell you when it lands.
  • Business: revenue and profit curves are often quadratic, and their roots mark break-even points.
  • Geometry: finding a rectangle’s dimensions from its area and perimeter leads directly to a quadratic.
  • Physics: stopping-distance and free-fall formulas are quadratic in time and speed.
Root (zero)
A value of xx that makes the equation true — where the parabola crosses the x-axis.
Discriminant
The quantity b24acb^2 - 4ac under the square root in the quadratic formula; its sign predicts the number and type of roots.
Vertex
The highest or lowest point of the parabola, at x=b2ax = -\frac{b}{2a} — exactly halfway between the two roots.
Coefficient
The numbers aa, bb, cc multiplying each power of xx in standard form.
02Formulas

The formulas you need

Keep these on hand — every method below builds on them.

Standard form
ax2+bx+c=0,a0ax^2 + bx + c = 0,\quad a \neq 0

Always rearrange into this form first — every method below assumes it.

Quadratic formula
x=b±b24ac2ax = \frac{-b \pm \sqrt{b^2 - 4ac}}{2a}

Works on every quadratic, whether or not it factors.

Discriminant
Δ=b24ac\Delta = b^2 - 4ac

Δ > 0: two real roots · Δ = 0: one repeated root · Δ < 0: two complex roots.

Factored form
a(xr1)(xr2)=0a(x - r_1)(x - r_2) = 0

The roots r₁ and r₂ multiply to c/a and add up to −b/a (Vieta’s formulas).

03Methods

How to solve quadratic equations

Pick the method that fits the problem in front of you.

When to use it: Fastest when the coefficients are small integers and the equation factors cleanly — typical for most homework problems. Try it first.
  1. 1Put the equation in standard form: ax2+bx+c=0ax^2 + bx + c = 0.
  2. 2For a=1a = 1: find two numbers that multiply to cc and add to bb.
  3. 3Rewrite as a product of two binomials: (xr1)(xr2)=0(x - r_1)(x - r_2) = 0.
  4. 4Set each factor equal to zero and solve the two mini-equations.
  5. 5Check both answers by substituting them back into the original equation.
04Worked examples

Quadratic Equations, solved step by step

From easy to hard — pick a problem to see its full solution.

x25x+6=0x^2 - 5x + 6 = 0
  1. 1Look for two numbers that multiply to 66 and add to 5-5: they are 2-2 and 3-3.
  2. 2Factor: (x2)(x3)=0(x - 2)(x - 3) = 0.
  3. 3Set each factor to zero: x2=0x - 2 = 0 or x3=0x - 3 = 0.
  4. 4Solve: x=2x = 2 or x=3x = 3.

Try it on your own quadratic equations homework

Photo Math Solver reads a quadratic equation directly from a screenshot — a textbook page, a PDF worksheet, an online quiz — and returns the full solution: the method it used, every intermediate step, and both roots. No retyping ax² + bx + c into a calculator, and no guessing whether it factors.

05Practice

Now you try

Work each one on paper first, then check your answer.

Problem 1
x27x+12=0x^2 - 7x + 12 = 0
Problem 2
x24x5=0x^2 - 4x - 5 = 0
Problem 3
3x25x+2=03x^2 - 5x + 2 = 0
Problem 4
x2+4x+1=0x^2 + 4x + 1 = 0

Stuck on your quadratic equations homework? Screenshot it

Quadratics with messy coefficients or fractions are easy to mistype into a calculator. Screenshot the equation with Photo Math Solver wherever you find it — a PDF worksheet, a textbook photo, an online quiz — and get every step without re-entering the numbers by hand.

06Common mistakes

Where points get lost

Each of these shows up on real graded work — and each has a simple fix.

Dropping the ±\pm and reporting only one root.Calculators and mental shortcuts return a single square root, so the second solution silently disappears.Every time you take a square root while solving, write ±\pm immediately — before simplifying anything else — and carry both branches to the end.
Mis-computing the discriminant when bb or cc is negative.The double negative in 4ac-4ac trips people up: for c=2c = -2, the term 4ac-4ac becomes positive, which feels wrong when rushing.Write the substitution with explicit parentheses first — Δ=(3)24(2)(2)\Delta = (3)^2 - 4(2)(-2) — and only then evaluate the signs.
Dividing both sides by xx in equations like x2=5xx^2 = 5x.Dividing by xx looks like legitimate simplification, but it quietly assumes x0x \neq 0 and destroys one of the two roots.Move everything to one side and factor instead: x25x=0x^2 - 5x = 0 gives x(x5)=0x(x - 5) = 0, so x=0x = 0 or x=5x = 5.
Applying the formula before the equation is in standard form.Problems are often given as 2x2=3x2x^2 = 3 - x, and it is tempting to read aa, bb, cc straight off the page as written.Rearrange to 2x2+x3=02x^2 + x - 3 = 0 first, and only then identify a=2a = 2, b=1b = 1, c=3c = -3.
Treating a negative discriminant as "no solution."Many courses first teach "no real solution," and the shorter phrase "no solution" sticks.Say "no real solutions" and, if your course covers complex numbers, finish the problem: 16=4i\sqrt{-16} = 4i leads to a perfectly valid pair of complex roots.

Photo Math Solver shows every intermediate step, so slips like these are easy to catch before they cost you marks.

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